| 代码 |
结果 |
a+b |
 |
x_i |
 |
x_1^2 |
 |
x_{22} |
 |
x^{(n)} |
%7D) |
^*x^* |
 |
x_{abcd}^{efgh} |
 |
\frac{x+y}{2} |
 |
\frac{1}{1+\frac{1}{2}} |
 |
\sqrt[3]{3} |
![\sqrt[3]{3}](https://math.jianshu.com/math?formula=%5Csqrt%5B3%5D%7B3%7D) |
\sqrt[3]{1+\sqrt[3]{3}} |
![\sqrt[3]{1+\sqrt[3]{3}}](https://math.jianshu.com/math?formula=%5Csqrt%5B3%5D%7B1%2B%5Csqrt%5B3%5D%7B3%7D%7D) |
\sum_{k=1}^{n} \frac{1}{1+k} |
 |
\int_{a}^{b} \frac{1}{1+x} dx |
 |
\int_{a}^{b} f(x)dx |
dx) |
a\!b |
 |
ab |
 |
a\,b |
 |
a\;b |
 |
a\ b |
 |
a\quad b |
 |
a\qquad b |
 |
\int_a^b f(x) \, dx |
%20%5C%2C%20dx) |
() |
) |
[] |
![[]](https://math.jianshu.com/math?formula=%5B%5D) |
\{ \} |
 |
| |
 |
\left( \sum_{i=1}^n \frac{x^2}{1-x} \right) |
) |
\begin{matrix} 1&2 \\\\ 3&4 \end{matrix} |
 |
\begin{pmatrix} 1&2 \\\\ 3&4 \end{pmatrix} |
 |
\begin{bmatrix} 1&2 \\\\ 3&4 \end{bmatrix} |
 |
\begin{vmatrix} 1&2 \\\\ 3&4 \end{vmatrix} |
 |
\begin{Vmatrix} 1&2 \\\\ 3&4 \end{Vmatrix} |
 |
\mathbf{I} |
 |
\mathbb{I} |
 |
I |
 |
\mbox{what} |
 |
\begin{aligned} x = {}& a+b+c+{} \\\\ &d+e+f+g \end{aligned} |
 |
\begin{aligned} x = a+b+c+{} \\\\ &&&&&d+e+f+g \end{aligned} |
 |
\alpha |
 |
{alpha} |
 |
|
\mathbf{X} = \left( \begin{matrix}
x\_11 & x\_12 & \ldots \\\\
x\_21 & x\_22 & \ldots \\\\
\vdots & \vdots & \ddots
\end{matrix} \right)
)
\mathbf{X} = \left( \begin{array}{ccc}
x_{11} & x_{12} & \ldots \\\\
x_{21} & x_{22} & \ldots \\\\
\vdots & \vdots & \ddots
\end{array}
\right)
)
\begin{gathered}
a=b+c+d \\\\
x=y+z
\end{gathered}
\begin{aligned}
a&=b+c+d \\\\
x&=y+z
\end{aligned}
y=\begin{cases}
-x, \quad x \leq 0 \\\\
x, \quad x > 0
\end{cases}
\left(
\begin{array}{|c|c|}
1&2 \\\\
\hline
3&4
\end{array}
\right)
)
\begin{array}{|c|c|}
\hline
1&2 \\\\
\hline
3&4 \\\\
\hline
\end{array}
最后编辑于 ：
©著作权归作者所有,转载或内容合作请联系作者
平台声明：文章内容（如有图片或视频亦包括在内）由作者上传并发布，文章内容仅代表作者本人观点，简书系信息发布平台，仅提供信息存储服务。
