iOS 获取当前正在显示的ViewController

代码干货IP属地: 北京
字数 129阅读 6,400

我们在非视图类中想要随时展示一个view时,需要将被展示的view加到当前view的子视图,或用当前view presentViewController,或pushViewContrller,这些操作都需要获取当前正在显示的ViewController。
UIViewController+Utils.h
<pre>

import <UIKit/UIKit.h>

@interface UIViewController (Utils)

+(UIViewController*) currentViewController;
@end
</pre>

UIViewController+Utils.m
<pre>

import "UIViewController+Utils.h"

@implementation UIViewController (Utils)
+(UIViewController) findBestViewController:(UIViewController)vc {
if (vc.presentedViewController) {
// Return presented view controller
return [UIViewController findBestViewController:vc.presentedViewController];

} else if [vc isKindOfClass:[UISplitViewController class]]) {

    // Return right hand side
    UISplitViewController* svc = (UISplitViewController*) vc;
    if (svc.viewControllers.count > 0)
        return [UIViewController findBestViewController:svc.viewControllers.lastObject];
    else
        return vc;

} else if ([vc isKindOfClass:[UINavigationController class]]) {

    // Return top view
    UINavigationController* svc = (UINavigationController*) vc;
    if (svc.viewControllers.count > 0)
        return [UIViewController findBestViewController:svc.topViewController];
    else
        return vc;

} else if ([vc isKindOfClass:[UITabBarController class]]) {

    // Return visible view
    UITabBarController* svc = (UITabBarController*) vc;
    if (svc.viewControllers.count > 0)
        return [UIViewController findBestViewController:svc.selectedViewController];
    else
        return vc;

} else {

    // Unknown view controller type, return last child view controller
    return vc;

}

}

+(UIViewController*) currentViewController {

// Find best view controller
UIViewController* viewController = [UIApplication sharedApplication].keyWindow.rootViewController;
return [UIViewController findBestViewController:viewController];

}

@end
</pre>

[原文转载](http://stackoverflow.com/questions/24825123/get-the-current-view-controller-from-the-app-delegate

最后编辑于
©著作权归作者所有,转载或内容合作请联系作者
平台声明:文章内容(如有图片或视频亦包括在内)由作者上传并发布,文章内容仅代表作者本人观点,简书系信息发布平台,仅提供信息存储服务。
16人点赞
更多精彩内容,就在简书APP
"小礼物走一走,来简书关注我"
还没有人赞赏,支持一下
代码干货我要成为会偷懒的程序员
总资产3共写了2.1W字获得335个赞共442个粉丝

推荐阅读更多精彩内容